Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 38

Answer

$\frac{3}{x}, with$ $x\ne0,-3$

Work Step by Step

Given : $\frac{3x+9}{x} \div (x+3)$ This becomes : $\frac{3(x+3)}{x} \times \frac{1}{x+3}$ $= \frac{3(x+3)}{x} \times \frac{1}{x+3}= \frac{3}{x} $ (After dividing out the common factor (x+3))
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