Answer
$\frac{3}{x}, with$ $x\ne0,-3$
Work Step by Step
Given : $\frac{3x+9}{x} \div (x+3)$
This becomes : $\frac{3(x+3)}{x} \times \frac{1}{x+3}$
$= \frac{3(x+3)}{x} \times \frac{1}{x+3}= \frac{3}{x} $
(After dividing out the common factor (x+3))