Answer
$ \frac{12x+3}{x-1}, with$ $x\ne1$
Work Step by Step
$\frac{4x+1}{5x+10} \times \frac{30x+60}{2x-2}$
$= \frac{4x+1}{5(x+2)} \times \frac{30(x+2)}{2(x-1)}$
$= \frac{12x+3}{x-1}$
(After dividing out the common factors $(x+2),2,5$)
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