Answer
$=\frac{b-1}{3b+3}$
with $b \ne -1$
Work Step by Step
$\frac{4b-1}{\frac{b^2+2b+1}{\frac{12b-3}{b^2-1}}}$
$=\frac{4b-1}{(b+1)^2}\times\frac{(b-1)(b+1)}{3(4b-1)}$
$=\frac{b-1}{3(b+1)}$
$=\frac{b-1}{3b+3}$
with $b \ne -1$
Algebra 1: Common Core (15th Edition)
by Charles, Randall I.
Published by
Prentice Hall
ISBN 10:
0133281140
ISBN 13:
978-0-13328-114-9
Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 41
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