Answer
$-\frac{1}{3}$
Work Step by Step
Given : $\frac{x-3}{6} \div \frac{3-x}{2}$
This becomes : $\frac{x-3}{6} \times \frac{2}{-(x-3)}$
$= \frac{x-3}{6} \times \frac{2}{-(x-3)}=-\frac{1}{3}$
(After dividing out the common factors $2$ $and$ $(x-3)$)