Answer
$=\frac{m^2-2m}{m^2+m-2}$
with $m \ne1 $ and $m \ne -2$
Work Step by Step
$\frac{m-2}{m+2}.\frac{m}{m-1}$
Multiply
$=\frac{m(m-2)}{(m+2)(m-1)}$
$=\frac{m^2-2m}{m^2-m+2m-2}$
$=\frac{m^2-2m}{m^2+m-2}$
with $m \ne1 $ and $m \ne -2$
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