Answer
$\frac{(x-1)(x-2)}{3}$
Work Step by Step
$(x^2-1)\times\frac{x-2}{3x+3}$
$=(x-1)(x+1)\times\frac{x-2}{3(x+1)}$
$=\frac{(x-1)(x+1)(x-2)}{3(x+1)}$
$=\frac{(x-1)(x-2)}{3}$
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