Answer
$=\frac{(w-3)(w+3)}{4}$
Work Step by Step
$(w^2-8w+15)\times\frac{w+3}{4w-20}$
$=(w^2-5w-3w+15)\times\frac{w+3}{4(w-5)}$
$=[w(w-5)-3(w-5)]\times\frac{w+3}{4(w-5)}$
$=(w-3)(w-5)\times\frac{w+3}{4(w-5)}$
$=\frac{(w-3)(w+3)(w-5)}{4(w-5)}$
$=\frac{(w-3)(w+3)}{4}$