Algebra 1: Common Core (15th Edition)

Published by Prentice Hall
ISBN 10: 0133281140
ISBN 13: 978-0-13328-114-9

Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 28

Answer

$=\frac{(w-3)(w+3)}{4}$

Work Step by Step

$(w^2-8w+15)\times\frac{w+3}{4w-20}$ $=(w^2-5w-3w+15)\times\frac{w+3}{4(w-5)}$ $=[w(w-5)-3(w-5)]\times\frac{w+3}{4(w-5)}$ $=(w-3)(w-5)\times\frac{w+3}{4(w-5)}$ $=\frac{(w-3)(w+3)(w-5)}{4(w-5)}$ $=\frac{(w-3)(w+3)}{4}$
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