Chapter 11 - Rational Expressions and Functions - 11-2 Multiplying and Dividing Rational Expressions - Practice and Problem-Solving Exercises - Page 674: 37

$\frac{n-3}{4n+5}$

$\frac{2n^2-5n-3}{4n^2-12n-7}\div\frac{4n+5}{2n-7}$ $=\frac{2n^2-6n+n-3}{4n^2+2n-14n-7}\times\frac{2n-7}{4n+5}$ $=\frac{2n(n-3)+(n-3)}{2n(2n+1)-7(2n+1)}\times\frac{2n-7}{4n+5}$ $=\frac{(2n+1)(n-3)}{(2n+1)(2n-7)}\times\frac{2n-7}{4n+5}$ $=\frac{(n-3)(2n-7)}{(2n-7)(4n+5)}$ $=\frac{n-3}{4n+5}$