Answer
$t-4$
Work Step by Step
Given :
$\frac{(t^{2}-t-12)}{t+1} \times \frac{t+1}{t+3}$
$= \frac{(t+3)(t-4)}{(t+1)} \times \frac{(t+1)}{(t+3)}$
$= t-4$
(After dividing out the common factors $(t+3)$ and $(t+1)$).
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