Answer
$K = 0.75~J$
Work Step by Step
We can find $K$:
$K = mgy-\frac{1}{2}ky^2$
$K = mg(- \Delta y)-\frac{1}{2}ky^2$
$K = (20~N)(0.050~m)-\frac{1}{2}(200~N/m)(-0.050~m)^2$
$K = 1.0~J-0.25~J$
$K = 0.75~J$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 212: 130a
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
