Answer
The rate at which electrical energy could be supplied is $~~2.7\times 10^9~W$
Work Step by Step
We can find the change in gravitational potential energy each second:
$\Delta U = mg~\Delta h$
$\Delta U = (5.5\times 10^6~kg)(9.8~m/s^2)(-50~m)$
$\Delta U = -2.7\times 10^9~J$
The decrease in gravitational potential energy each second is $~~-2.7\times 10^9~J$
Note that this amount is the decrease in gravitational potential energy each second.
We can find the rate at which electrical energy could be supplied:
$P = \frac{E}{t}$
$P = \frac{2.7\times 10^9~J}{1~s}$
$P = 2.7\times 10^9~W$
The rate at which electrical energy could be supplied is $~~2.7\times 10^9~W$
