Answer
$v = 1.9~m/s$
Work Step by Step
We can find the height $h$ above the lowest point when the angle is $30.0^{\circ}$:
$\frac{L-h}{L} = cos~\theta$
$L-h = L~cos~\theta$
$h = L~(1-cos~\theta)$
$h = (1.4~m)~(1-cos~30.0^{\circ})$
$h = 0.19~m$
The kinetic energy at the lowest point is equal to the potential energy at the highest point:
$\frac{1}{2}mv^2 = mgh$
$v^2 =2gh$
$v =\sqrt{2gh}$
$v =\sqrt{(2)(9.8~m/s^2)(0.19~m)}$
$v = 1.9~m/s$
