Answer
doesnt depend on angle
Work Step by Step
$\dfrac {mv^{2}_{1}}{2}=\dfrac {mv^{2}_{0}}{2}+mgh\Rightarrow v_{1}=\sqrt {v^{2}_{0}+2gh}$
As you can see it doesnt depend on the angle or mass of the ball but only depends on the height and initial speed.
