Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 8 - Potential Energy and Conservation of Energy - Problems - Page 212: 129

Answer

$$\approx 3.17\times 10^{11}W$$

Work Step by Step

Since two thirds evaporates and one third stays, then: $$E=mgh=\dfrac {1}{3}\times p\times A\times d\times h\times g=\dfrac {1}{3}\times 1000\times 8\times 10^{6}\times 10^{6}\times 75\times 10^{-2}\times 500\times 10$$ $$=\dfrac {1}{3}\times 1000\times 8\times 10^{6}\times 10^{6}\times 75\times 10^{-2}\times 500\times 10=10^{19}J\Rightarrow W=\dfrac {10^{19}}{365\times 24\times 360}$$ $=\dfrac {10^{19}}{365\times 24\times 3600}\approx 3.17\times 10^{11}W$
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