Answer
9.19 m/s
Work Step by Step
The pole is 4.3m long and the firefighter starts at rest. As he falls, his acceleration will be g = 9.81 $m/s^2$ To find his final velocity we use the equation:
$v^2 = v_{0}^2 + 2a\Delta x$
we find that v = 9.19 m/s