Answer
The half-life of $^{197}Hg$ is $~~64.2~hours$
Work Step by Step
We can find the half-life of $^{197}Hg$:
$T_{1/2} = \frac{ln~2}{\lambda}$
$T_{1/2} = \frac{ln~2}{0.0108~h^{-1}}$
$T_{1/2} = 64.2~hours$
The half-life of $^{197}Hg$ is $~~64.2~hours$
