Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 42 - Nuclear Physics - Problems - Page 1303: 13

Answer

$r = 13.3~km$

Work Step by Step

We can find the volume of the sun after it collapsed: $\rho = \frac{M_s}{V} = 2\times 10^{17}~kg/m^3$ $V = \frac{1.99\times 10^{30}~kg}{2\times 10^{17}~kg/m^3}$ $V = 9.95\times 10^{12}~m^3$ We can find the radius of the sun: $V = \frac{4}{3}\pi~r^3 = 9.95\times 10^{12}~m^3$ $r^3 = \frac{(3)(9.95\times 10^{12}~m^3)}{4\pi}$ $r = \sqrt[3] {\frac{(3)(9.95\times 10^{12}~m^3)}{4\pi}}$ $r = 1.33\times 10^4~m$ $r = 13.3~km$
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