Answer
$$7.07 \mathrm{\ MeV}
$$
Work Step by Step
The binding energy per nucleon is
$$
\Delta E_{\text {ben }}=\Delta E_{\text {be }} / A=28.3 \mathrm{MeV} / 4=7.07 \mathrm{MeV} .
$$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 42 - Nuclear Physics - Problems - Page 1303: 22e
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