Answer
$E = 1.2\times 10^5~eV$
Work Step by Step
We can find the photon energy:
$E = \frac{hc}{\lambda}$
$E = \frac{(6.63\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{10\times 10^{-12}~m}$
$E = 1.989\times 10^{-14}~J$
$E = (1.989\times 10^{-14}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$
$E = 1.2\times 10^5~eV$
