Answer
$E = 1.24\times 10^9~eV$
Work Step by Step
We can find the photon energy:
$E = \frac{hc}{\lambda}$
$E = \frac{(6.63\times 10^{-34}~J~s)(3.0\times 10^8~m/s)}{1.00\times 10^{-15}~m}$
$E = 1.989\times 10^{-10}~J$
$E = (1.989\times 10^{-10}~J)(\frac{1~eV}{1.6\times 10^{-19}~J})$
$E = 1.24\times 10^9~eV$
