Answer
$nn^*$ is a positive real number.
Work Step by Step
$n = a + ib$
We can find an expression for $nn^*$:
$nn^* = (a + ib)(a - ib)$
$nn^* = a^2+b^2$
Since $a$ and $b$ are positive or negative real numbers, $a^2+b^2$ is a positive real number.
Therefore, $nn^*$ is a positive real number.