Answer
The least uncertainty in any simultaneous measurement of the momentum component is $~~2.1\times 10^{-24}~kg~m/s$
Work Step by Step
$\Delta x~\Delta p \geq \hbar$
$\Delta p \geq \frac{\hbar}{\Delta x}$
$\Delta p \geq \frac{1.05\times 10^{-34}~J~s}{50\times 10^{-12}~m}$
$\Delta p \geq 2.1\times 10^{-24}~kg~m/s$
The least uncertainty in any simultaneous measurement of the momentum component is $~~2.1\times 10^{-24}~kg~m/s$
