Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Foundations - Topic B - Energy - Exercises - Page 24: B.9(b)

Answer

Its temperature would rise by $8670 \space K$.

Work Step by Step

$$\Delta U = C \Delta T$$ $$\frac{\Delta U}{C}= \Delta T$$ $$\frac{50.0 \space kJ}{5.77 \space JK^{-1}} = \Delta T$$ $$\Delta T = \frac{50.0 \space kJ}{5.77 \space JK^{-1}} \times \frac{1000 \space J}{1 \space kJ} = 8670 \space K$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.