Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Foundations - Topic B - Energy - Exercises - Page 24: B.9(a)

Answer

The temperature would rise by $27.2 \space K$

Work Step by Step

$$\Delta U = C \Delta T$$ $$\frac{\Delta U}{C}= \Delta T$$ $$\frac{100 \space J}{3.67 \space JK^{-1}} = \Delta T$$ $$\Delta T = 27.2 \space K$$
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