Answer
The final speed of the electron is $1.875\times 10^{8}$ $m/s$
Th energy of the electron in electron volts unit is given by $10^5$ $eV$
Work Step by Step
If $m$ be the mass of the electron and $v$ is its final speed, then
$\frac{1}{2}mv^2=e\Delta\phi$
or, $v=\sqrt {\frac{2e\Delta\phi}{m}}$
or, $v=\sqrt {\frac{2\times1.6\times 10^{-19}\times100\times 10^3}{9.1\times 10^{-31}}}$
$v\approx1.875\times 10^{8}$ $m/s$
$\therefore$ The final speed of the electron is $1.875\times 10^{8}$ $m/s$
Th energy of the electron in electron volts unit is given by
$E=100\times10^3$ $eV$ $=10^5$ $eV$
