Physical Chemistry: Thermodynamics, Structure, and Change

Published by W. H. Freeman
ISBN 10: 1429290196
ISBN 13: 978-1-42929-019-7

Foundations - Topic B - Energy - Exercises - Page 24: B.10(b)

Answer

$$417 \space J$$

Work Step by Step

Molar mass of water $(H_2O)$ = $(16.00 + 1.01 * 2) \space g/mol = 18.02 \space g/mol$ $\Delta T = 10.0 \space ^oC = 10.0 \space K$* * Only for temperature differences $(\Delta T)$ - Rearranging to do a dimensional analysis: $$10.0 \space g \times \frac{1 \space mol}{18.02 \space g} \times 10.0 \space K \times \frac{75.2 \space J}{\space K \space mol} = 417 \space J$$
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