Answer
$$\sec^2\theta-1=(\sec\theta-1)(\sec\theta+1)$$
Work Step by Step
$$A=\sec^2\theta-1$$
We factor the expression like normal, using $$a^2-b^2=(a-b)(a+b)$$
Therefore, $$A=(\sec\theta-1)(\sec\theta+1)$$
Trigonometry (11th Edition) Clone
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
978-0-13-421743-7
ISBN 13:
978-0-13421-743-7
Chapter 5 - Trigonometric Identities - Section 5.2 Verifying Trigonometric Identities - 5.2 Exercises - Page 208: 24
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