Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 84

Answer

See below.

Work Step by Step

$LHS=\frac{sin^3\theta+cos^3\theta}{1-2cos^2\theta}=\frac{(sin\theta+cos\theta)(sin^2\theta-sin\theta cos\theta+cos^2\theta)}{sin^2\theta-cos^2\theta}=\frac{1-sin\theta cos\theta}{sin\theta-cos\theta}=\frac{1-sin\theta cos\theta}{sin\theta-cos\theta}\times\frac{1/cos\theta}{1/cos\theta}=\frac{sec\theta-sin\theta}{tan\theta-1}=RHS$
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