Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 72

Answer

See below.

Work Step by Step

$LHS=\frac{sin^2\theta-tan\theta}{cos^2\theta-cot\theta}=\frac{sin\theta(sin\theta-sec\theta)}{cos\theta(cos\theta-csc\theta)}=\frac{sin\theta(sin\theta-sec\theta)}{cos\theta(cos\theta-csc\theta)}\times\frac{cos\theta}{sin\theta}\times\frac{sin\theta}{cos\theta}=\frac{sin^2\theta(sin\theta cos\theta-1)}{cos^2\theta(cos\theta sin\theta-1)}=tan^2\theta=RHS$
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