Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 62

Answer

See below.

Work Step by Step

$RHS=\frac{sin\theta+1}{cos\theta}=\frac{sin\theta+1}{cos\theta}\times\frac{sin\theta+cos\theta-1}{sin\theta+cos\theta-1}=\frac{sin^2\theta-1+sin\theta cos\theta+cos\theta}{cos\theta(sin\theta+cos\theta-1)}=\frac{-cos^2\theta+sin\theta cos\theta+cos\theta}{cos\theta(sin\theta+cos\theta-1)}=\frac{-cos\theta+sin\theta +1}{sin\theta+cos\theta-1}=LHS$
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