Answer
$ 2$
Work Step by Step
$\frac{(tan\theta+1)(tan\theta+1)-sec^2\theta}{tan\theta}
=\frac{tan^2\theta+2tan\theta+1-sec^2\theta}{tan\theta}
=\frac{sec^2\theta+2tan\theta-sec^2\theta}{tan\theta}
=\frac{2tan\theta}{tan\theta}
=2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 16
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