Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 61

Answer

See below.

Work Step by Step

$RHS=tan\theta+sec\theta=(tan\theta+sec\theta)\times\frac{tan\theta-sec\theta+1}{tan\theta-sec\theta+1}=\frac{tan^2\theta-sec2\theta+tan\theta+sec\theta}{tan\theta-sec\theta+1}=\frac{-1+tan\theta+sec\theta}{tan\theta-sec\theta+1}=LHS$
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