Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 25

Answer

See below.

Work Step by Step

$LHS=tan(u)cot(u)-cos^2(u)=\frac{sin(u)}{cos(u)}\cdot\frac{cos(u)}{sin(u)}-cos^2(u)=1-cos^2(u)=sin^2(u)=RHS$
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