Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.4 Trigonometric Identities - 6.4 Assess Your Understanding - Page 497: 34

Answer

The left side of the equation is equivalent to $1$ therefore the given equation is an identity. Refer to the solution below.

Work Step by Step

\begin{align} \text{LHS }&= \tan^2{\theta} \cos^2{\theta}+\cot^2{\theta} \sin^2{\theta}\\[3mm] &= \dfrac{\sin^2{\theta}}{\cos^2{\theta}} \dot \cos^2{\theta} + \dfrac{\cos^2{\theta}}{\sin^2{\theta}} \cdot \sin^2{\theta}\\[3mm] &= \sin^2{\theta}+\cos^2{\theta} \\[3mm] & = 1 \\[3mm] & = \text{ RHS} \end{align}
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