Answer
$1,5$
Work Step by Step
$\sqrt {3x+1}-\sqrt {x-1}=2$
$\sqrt {3x+1}=\sqrt {x-1}+2$
$3x+1=x-1+4\sqrt {x-1}+4$
$2x-2=4\sqrt {x-1}$
$x-1=2\sqrt {x-1}$
$x^2-2x+1=4x-4$
$x^2-6x+5=0$
$(x-5)(x-1)=0$
$x=1,5$
Check, both fit.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 57
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