Answer
$ -3, \frac{4}{3}, 3$
Work Step by Step
$3x^3+4x^2=27x+36$,
$3x^3-27x+4x^2-36=0$,
$3x(x^2-9)-4(x^2-9)=0$,
$(x^2-9)(3x-4)=0$,
$(3x-4)(x+3)(x-3)=0$,
thus $x=-3, \frac{4}{3}, 3$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 44
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