Answer
$ 8$
Work Step by Step
$3+\sqrt {3x+1}=x$
$\sqrt {3x+1}=x-3$
$3x+1=x^2-6x+9$
$x^2-9x+8=0$
$(x-1)(x-8)=0$
thus $x=1,8$
check, only $x=8$ fits.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 53
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