Answer
$ -2, \frac{1}{2}, 2$
Work Step by Step
$2x^3+4=x^2+8x$,
$2x^3-x^2-8x+4=0$,
$x^2(2x-1)-4(2x-1)=0$,
$(2x-1)(x^2-4)=0$,
$(2x-1)(x+2)(x-2)=0$,
thus $x=-2, \frac{1}{2}, 2$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 43
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