Answer
$-1$ (multiplicity 2) and $1$
Work Step by Step
$x^3+x^2-x-1=0$,
$x^2(x+1)-(x+1)=0$,
$(x+1)(x^2-1)=0$,
$(x+1)(x+1)(x-1)=0$,
thus $x=-1$ (multiplicity 2) and $x=1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 41
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
