Answer
$ 0,\pm3$
Work Step by Step
$t^3-9t=0$,
$t(t^2-9)=0$,
$t(t+3)(t-3)=0$,
thus $t=0,\pm3$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 31
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