Answer
a. $x$
b. $|x-3|$
Work Step by Step
By using the facts that $\sqrt[n]{a^n}=a$ if $n$ is odd and $\sqrt[n]{a^n}=|a|$ if $n$ is even, we have:
(a) Since $3$ is odd, then $\sqrt[3]{x^3}=x$
(b) Since $4$ is even, then $(\sqrt[4]{x-3})^4=|x-3|$