Answer
$ -4, -1, 1$
Work Step by Step
$x^3+4x^2-x-4=0$,
$x^2(x+4)-(x+4)=0$,
$(x+4)(x^2-1)=0$,
$(x+4)(x+1)(x-1)=0$,
thus $x=-4, -1, 1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 42
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