Answer
$ -7,0,1$
Work Step by Step
$x^3+6x^2-7x=0$,
$x(x^2+6x-7)=0$,
$x(x+7)(x-1)=0$,
thus $x=-7,0,1$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.8 Solving Equations - A.8 Assess Your Understanding - Page A70: 40
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