Answer
$ \frac{6x-4x^3}{3(1-x^2)^{4/3}}$
Work Step by Step
$\frac{2x(1-x^2)^{1/3}+\frac{2}{3}x^3(1-x^2)^{-2/3}}{(1-x^2)^{2/3}}=\frac{6x(1-x^2)+2x^3}{3(1-x^2)^{4/3}}=\frac{6x-4x^3}{3(1-x^2)^{4/3}}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 88
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