Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 80

Answer

$ \frac{65x+6}{24\sqrt[3] {(x-2)^2(8x+1)^2}}$

Work Step by Step

$\frac{\sqrt[3] {8x+1}}{3\sqrt[3] {(x-2)^2}}+\frac{\sqrt[3] {x-2}}{24\sqrt[3] {(8x+1)^2}}=\frac{8(8x+1)+(x-2)}{24\sqrt[3] {(x-2)^2(8x+1)^2}}=\frac{65x+6}{24\sqrt[3] {(x-2)^2(8x+1)^2}}$
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