Answer
$ \frac{65x+6}{24\sqrt[3] {(x-2)^2(8x+1)^2}}$
Work Step by Step
$\frac{\sqrt[3] {8x+1}}{3\sqrt[3] {(x-2)^2}}+\frac{\sqrt[3] {x-2}}{24\sqrt[3] {(8x+1)^2}}=\frac{8(8x+1)+(x-2)}{24\sqrt[3] {(x-2)^2(8x+1)^2}}=\frac{65x+6}{24\sqrt[3] {(x-2)^2(8x+1)^2}}$