Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 43

Answer

$\dfrac{\sqrt 2}{2}$

Work Step by Step

We rationalize the denominator by multiplying both numerator and denominator by $\sqrt 2$: $$ \frac{1}{\sqrt 2}=\frac{\sqrt 2}{\sqrt 2 \sqrt 2}=\frac{\sqrt 2}{2} $$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.