Answer
$ \frac{4}{(x^2+4)^{3/2}}$
Work Step by Step
$\frac{(x^2+4)^{1/2}-x^2(x^2+4)^{-1/2}}{x^2+4}=\frac{(x^2+4)-x^2}{(x^2+4)^{3/2}}=\frac{4}{(x^2+4)^{3/2}}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 86
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