Answer
$ \frac{8}{x^3y}$
Work Step by Step
$\frac{(4x^{-1}y^{1/3})^{3/2}}{(xy)^{3/2}}=[\frac{2^{6}x^{-3}y}{x^3y^3}]^{1/2}=[\frac{2^{6}}{x^6y^2}]^{1/2}=\frac{8}{x^3y}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 74
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
