Answer
$ \frac{9-5\sqrt 3}{3} $
Work Step by Step
$\frac{\sqrt 3-1}{2\sqrt 3+3}=\frac{\sqrt 3-1}{2\sqrt 3+3}\times\frac{2\sqrt 3-3}{2\sqrt 3-3}=\frac{6-3\sqrt 3-2\sqrt 3+3}{12-9}=\frac{9-5\sqrt 3}{3} $
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.7 nth Roots; Rational Exponents - A.7 Assess Your Understanding - Page A61: 50
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