Answer
$\frac{8x^{5/4}}{y^{3/4}}$
Work Step by Step
$\frac{(16x^2y^{-1/3})^{3/4}}{(xy^2)^{1/4}}=[\frac{2^{12}x^6y^{-1}}{xy^2}]^{1/4}=[\frac{2^{12}x^5}{y^3}]^{1/4}=\frac{8x^{5/4}}{y^{3/4}}$
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